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December 19, 2014

December 19, 2014

Posted by **Britt** on Monday, September 2, 2013 at 4:08pm.

Find the composite functions f o g and g o f for the given functions.

f(x) = 10^x and g(x) = log x

State the domain and range for each:

f(x) = 4x + 1 and g(x) = x^2

f(x) = sin x and g(x) = x^2 - x + 1

f(x) = 10^x and g(x) = log x

If f = {(-2,-1), (-1,2), (0,6), (1,3), (2,-1), (3,-5), (4,0), (5,8)} and g = {(-2,6), (-1,5), (0,-8), (1,3), (2,9), (3,9), (4,0), (5,-2)}, then find f o g and g o f.

and how on earth would I figure this out?

By graphing the functions, determine the region where log2(x+3) > 2x.

- Calculus -
**Steve**, Monday, September 2, 2013 at 6:43pm(f◦g)(x) = f(g(x))

f(x) = 10^x, so

f(g) = 10^g = 10^(logx) = x

Similarly, g◦f = x

Note that 10^x and logx are inverse functions

domain for all polynomials is all reals

g(x) = x^2 has range y>=0

g(x) = x^2-x+1 = (x-1/2)^2 + 3/4 has range y >= 3/4

since 10^x and logx are inverses, and the range of 10^x is y>0, the domain of logx is x>0

When given actual pairs, just pug and chug

(f◦g)(-2) = f(g(-2)) = f(6) is undefined

(g◦f)(-2) = g(f(-2)) = g(-1) = 5

and so on

Visit wolframalpha.com and enter

plot y=log2(x+3) and y=2x

to see the graphs. Note that the lower solution is not exactly -3, since log(0) is not defined.

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