Posted by **Leda** on Monday, September 2, 2013 at 6:03am.

The first term of a geometric progression is more than the third term by 12. The fourth term is more than the second term by 4. Find:

i.the first term a and the common ratio r.

ii. the n'th term of the progression.

- Math Algebra -
**Graham**, Monday, September 2, 2013 at 7:01am
Geometric Progression: x(n) = a r^n

First term x(0) = a

Second term x(1) = ar

etc.

So

a = ar^2 +12

ar^3 = ar +4

Rearranging gives,

a(1-r^2) = 12

a(1-r^2)r = -4

Thus solve for r by dividing,

Substitute into the original to solve for a,

- Math Algebra -
**Leda**, Monday, September 2, 2013 at 7:35am
Omg im really sorry. There seems to be an error. The "fifth" term of a geometric progression is more than the third term by 12.

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