Posted by **Leda** on Monday, September 2, 2013 at 6:03am.

The first term of a geometric progression is more than the third term by 12. The fourth term is more than the second term by 4. Find:

i.the first term a and the common ratio r.

ii. the n'th term of the progression.

- Math Algebra -
**Graham**, Monday, September 2, 2013 at 7:01am
Geometric Progression: x(n) = a r^n

First term x(0) = a

Second term x(1) = ar

etc.

So

a = ar^2 +12

ar^3 = ar +4

Rearranging gives,

a(1-r^2) = 12

a(1-r^2)r = -4

Thus solve for r by dividing,

Substitute into the original to solve for a,

- Math Algebra -
**Leda**, Monday, September 2, 2013 at 7:35am
Omg im really sorry. There seems to be an error. The "fifth" term of a geometric progression is more than the third term by 12.

## Answer this Question

## Related Questions

- math - The third term of a geometric progressiom is nine times the first term.if...
- math - The 3rd term of a geometric progression is nine times the first term.if ...
- Geometric progression - The second term of a geometric progression is 12 more ...
- Math - 3,5,-5... The first term in the sequence of #'s shown above is 3. Each ...
- math - the fourth term of an arithmetic progression is equal to 3 times the ...
- GP Caluculus - The third term of a geometric progression is 16. The sum of the ...
- Maths - The 3rd term of an AP is 10 more than the first term while the fifth ...
- arithmetic - first term and larst term of a geometric progression is 42.if the ...
- Math - The fifth term of an arithmetic progression is three times the second ...
- math - the 3rd term of a geometric progression is nine times the 1st term.if the...