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November 27, 2014

November 27, 2014

Posted by **JIll** on Sunday, September 1, 2013 at 8:17pm.

A:What is the velocity of the car in meters per second?

B:What is the acceleration of the car?

C:If your car were going twice the velocity, how far would it take to stop if the acceleration were the same as for part (B)?

D:How long would it take the car to stop if it were going at twice the velocity?

- physics -
**bobpursley**, Sunday, September 1, 2013 at 9:24pma. convert mi/h to m/s: A nice thing to remember is that 60miles/hr =88feet/sec=26.8 m/s

b. Vf^2=vi^2+2ad solve for a.

c. You can work it out, using the same a. However, think: if you are going twice as fast, you have twice squared (4) times as much KE, so fricion distance must be four times as far.

d. average velocity is twice, distance is four times,

distance=velavb*time

time=distance/velocityavy=4/2= twice as long.

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