If a 250.0 mL sealed plastic bag starts out at a temperature of 19.0 °C and after sitting in the sun reaches a temperature of 60.0 °C, what will the new volume of the bag be? Assume the pressure inside the bag remains constant.

To find the new volume of the bag, we need to use Charles's law, which states that the volume of a gas is directly proportional to its temperature.

Charles's law can be mathematically expressed as:
V1 / T1 = V2 / T2

Where:
V1 is the initial volume of the bag,
T1 is the initial temperature in Kelvin,
V2 is the unknown final volume of the bag,
T2 is the final temperature in Kelvin.

First, we need to convert the initial and final temperatures from Celsius to Kelvin. The Kelvin scale starts at absolute zero (0K), so we need to add 273.15 to each temperature:

T1 (initial temperature in Kelvin) = 19.0 °C + 273.15 = 292.15 K
T2 (final temperature in Kelvin) = 60.0 °C + 273.15 = 333.15 K

Now, we can solve for V2. Rearranging the formula, we have:

V2 = (V1 * T2) / T1

Substituting the given initial volume and temperatures:

V2 = (250.0 mL * 333.15 K) / 292.15 K

Calculating this expression:

V2 ≈ 285.9 mL

Therefore, the new volume of the bag after sitting in the sun will be approximately 285.9 mL.

PV = kT

if P remains constant, then

V = kT (with a new k, of course)

so, the V2 = (T2/T1)*V1

recall that T is in °K, not °C

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