Posted by **Shane** on Sunday, September 1, 2013 at 2:01am.

A circle x^2 + y^ + 2x - 2y -1 = 0 expressed in the following form (x-h)^2 + (y-k)^2 = r^2 where h, k are the coordinates of the centre. How is r the radius given?

- maths -
**Graham**, Sunday, September 1, 2013 at 2:15am
Rearrange into incomplete quadratics:

(x² + 2x) + (y² - 2y) = 1

Complete the squares:

(x² + 2x + 1) + (y² - 2y + 1) = 1 + 1 + 1

Express in the required form:

(x + 1)² + (y - 1)² = (√3)²

Thus: h = -1, k = 1, r = √3

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