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January 30, 2015

January 30, 2015

Posted by **Anonymous** on Sunday, September 1, 2013 at 12:25am.

- statistics -
**PsyDAG**, Sunday, September 1, 2013 at 1:55pmZ = (score-mean)/SEm

SEm = SD/√n

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.

- statistics -
**Linda**, Sunday, March 16, 2014 at 8:47pm(7.73/SQRT (24) = 1.577879643, next we subtract the data value (70) from the mean (73) as follows (70 – 73 = -3); the values of the two equations are divided as follows (-3/1.577879643 = 1.901285699).

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