A bus decrease it's speed from 80km/h to60km/h in 5min .find it's acceleration
(60-80)/5 = -4 km/h/min
You can convert that to m/s^2 or leagues/hr^2 of the units of your choice.
To find the acceleration of the bus, we can use the formula:
acceleration = (final velocity - initial velocity) / time
In this case, the initial velocity (u) is 80 km/h, the final velocity (v) is 60 km/h, and the time (t) is 5 minutes. However, we need to convert the time to seconds, as acceleration is typically calculated in meters per second squared (m/s²).
To convert minutes to seconds, we multiply the given time by 60 (1 minute = 60 seconds):
time = 5 minutes x 60 seconds/minute = 300 seconds
Now, we can substitute the values into the formula:
acceleration = (60 km/h - 80 km/h) / 300 seconds
Next, we need to convert the velocities from km/h to m/s. To do this, we divide by 3.6 (1 km/h = 1/3.6 m/s):
initial velocity (u) = 80 km/h / 3.6 = 22.22 m/s
final velocity (v) = 60 km/h / 3.6 = 16.67 m/s
Substituting these values into the formula:
acceleration = (16.67 m/s - 22.22 m/s) / 300 seconds
Finally, we can calculate the acceleration:
acceleration = -5.55 m/s / 300 s
acceleration ≈ -0.0185 m/s²
Therefore, the acceleration of the bus is approximately -0.0185 m/s², where the negative sign indicates a decrease in speed.