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July 1, 2015

July 1, 2015

Posted by **mohlomphegi** on Friday, August 30, 2013 at 3:53am.

- physical science -
**Steve**, Friday, August 30, 2013 at 5:07amsince the range and max height are

r = v^2 sin2θ/g = 25

h = v^2 sin^2θ/2g = 6

tanθ = 24/25

so you can find the initial v.

And of course, the height y is

y = vt - g/2 t^2

set y=0 to find the flight time t.