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April 1, 2015

April 1, 2015

Posted by **Melody** on Thursday, August 29, 2013 at 6:54pm.

thanks

- Maths/Physics -
**Damon**, Thursday, August 29, 2013 at 7:00pmfor all we know the acceleration is constant. I actually suspect the force is greatest when pushing off the starting block and therefore acceleration is greatest at the start (F = m a), but there is nothing in your statement to help us with a versus t. Therefore assume a is constant.

d = (1/2) a t^2

10 = (1/2) a (2^2)

20 = 4 a

a = 5 m/s^2 indeed

- Maths/Physics -
**Devron**, Friday, August 30, 2013 at 3:56amI think I know what you are looking for, so starting off where Damon left off:

Max acceleration occurs when the velocity=acceleration.

Vi=0m/s^2

Vf=5m/s and

a=5m/s^2

d=?

Solve for d.

Vf^2=Vi^2+2ad

(5m/s)^2=0+2(5m/s^2)d

25=10d

25/10=d

d=2.5m

The sprinters will not keep accelerating indefinitely, so I think this what your teacher/professor had in mind. But a better question would be when will the velocity equal the acceleration.

Best

BTW, I answered this in your earlier post.

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