Sunday

December 21, 2014

December 21, 2014

Posted by **Melody** on Thursday, August 29, 2013 at 6:54pm.

thanks

- Maths/Physics -
**Damon**, Thursday, August 29, 2013 at 7:00pmfor all we know the acceleration is constant. I actually suspect the force is greatest when pushing off the starting block and therefore acceleration is greatest at the start (F = m a), but there is nothing in your statement to help us with a versus t. Therefore assume a is constant.

d = (1/2) a t^2

10 = (1/2) a (2^2)

20 = 4 a

a = 5 m/s^2 indeed

- Maths/Physics -
**Devron**, Friday, August 30, 2013 at 3:56amI think I know what you are looking for, so starting off where Damon left off:

Max acceleration occurs when the velocity=acceleration.

Vi=0m/s^2

Vf=5m/s and

a=5m/s^2

d=?

Solve for d.

Vf^2=Vi^2+2ad

(5m/s)^2=0+2(5m/s^2)d

25=10d

25/10=d

d=2.5m

The sprinters will not keep accelerating indefinitely, so I think this what your teacher/professor had in mind. But a better question would be when will the velocity equal the acceleration.

Best

BTW, I answered this in your earlier post.

**Answer this Question**

**Related Questions**

Physics - An athlete is training and is required to perform shuttle runs. From ...

Physics URGENT HELP - An athlete is training and is required to perform shuttle ...

physics - A new event has been proposed for the Winter Olympics. An athlete will...

physics - A new event has been proposed for the Winter Olympics. An athlete will...

maths - two cyclists go around a race track repeatedly. the first cyclist takes ...

calculus - 6. The forward motion of a space shuttle, t seconds after touchdown, ...

calculus (gr 12) - The forward motion of a space shuttle, t seconds after ...

calculus (gr 12) - The forward motion of a space shuttle, t seconds after ...

calculus (gr 12) - The forward motion of a space shuttle, t seconds after ...

Grade 12 Calculus - The forward motion of a space shuttle, t seconds after ...