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October 1, 2014

October 1, 2014

Posted by **Melody** on Thursday, August 29, 2013 at 6:12pm.

Where would the maximum acceleration occur? Justify your answer.

Please help! Thankyou.

- Physics URGENT HELP -
**Damon**, Thursday, August 29, 2013 at 6:17pm10 = (1/2) a t^2

20 = a (4)

a = 5 m/s^2

- Physics URGENT HELP -
**Melody**, Thursday, August 29, 2013 at 6:42pmThankyou, but I need to establish where within the run max acceleration occurs (what metre mark?)

- Physics URGENT HELP -
**bobpursley**, Thursday, August 29, 2013 at 8:11pmI suspect if they turn around at the end, the max acceleration occurs there.

- Physics URGENT HELP -
**Devron**, Friday, August 30, 2013 at 2:02amI think I know what you were looking for. Starting off where Damon left off,

Max acceleration occurs when the velocity=acceleration.

Vi=0m/s^2

Vf=5m/s and

a=5m/s^2

d=?

Solve for d.

Vf^2=Vi^2+2ad

(5m/s)^2=0+2(5m/s^2)d

25=10d

25/10=d

d=2.5m

The runner establishes max acceleration at the 2.5m mark in the race.

Hope I helped in time.

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