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college algebra

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how to solve this x^2-14+49=16

  • college algebra - ,

    x^2-14x+49=16
    (x-7)^2 = 16
    x-7 = ±4
    x = 7±4 = 3,11

    or, just use the quadratic formula. Not really necessary here, since the left side was conveniently a perfect square.

    x^2 - 14x + 33 = 0
    x = (14±√(196-132))/2
    = (14±√64)/2
    = 7±4

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