college algebra
posted by jordan on .
how to solve this x^214+49=16

x^214x+49=16
(x7)^2 = 16
x7 = ±4
x = 7±4 = 3,11
or, just use the quadratic formula. Not really necessary here, since the left side was conveniently a perfect square.
x^2  14x + 33 = 0
x = (14±√(196132))/2
= (14±√64)/2
= 7±4