If 51J of heat is added to an aluminum can with a mass of 23.0g , what is its temperature change? Specific heat capacity of aluminum is 0.903 J/g∘C.
2.0
To find the temperature change of the aluminum can, we can use the formula:
Q = mcΔT
Where:
Q is the heat energy in Joules
m is the mass of the aluminum can in grams
c is the specific heat capacity of aluminum in J/g∘C
ΔT is the change in temperature in degrees Celsius
Given:
Q = 51J
m = 23.0g
c = 0.903 J/g∘C
We can rearrange the formula to solve for ΔT:
ΔT = Q / (mc)
Substituting the given values:
ΔT = 51J / (23.0g * 0.903 J/g∘C)
Calculating:
ΔT ≈ 2.38∘C
Therefore, the temperature change of the aluminum can is approximately 2.38∘C.