What is the answer for this problem?it is greater than 43 and less than 52.if you add the digits the sum is 8

To find the number that is greater than 43 and less than 52, and has a digit sum of 8, we can start by listing the possible numbers and checking their digit sums:

44: 4 + 4 = 8 (digit sum is 8)
45: 4 + 5 = 9 (digit sum is 9)
46: 4 + 6 = 10 (digit sum is 10)
47: 4 + 7 = 11 (digit sum is 11)
48: 4 + 8 = 12 (digit sum is 12)
49: 4 + 9 = 13 (digit sum is 13)
50: 5 + 0 = 5 (digit sum is 5)
51: 5 + 1 = 6 (digit sum is 6)

Therefore, the only number that is greater than 43, less than 52, and has a digit sum of 8 is 44.

To find the number that meets these requirements, we can start by listing all the possible numbers that are greater than 43 and less than 52: 44, 45, 46, 47, 48, 49, 50, and 51.

Next, we need to check if the sum of the digits in each of these numbers is 8. We can do this by adding the digits in each number. For example, for 44, the sum of the digits is 4 + 4 = 8.

Continuing this process for all the numbers, we find that the only number where the sum of the digits is 8 is 44. Therefore, the answer to this problem is 44.

Which one of these is the answer?

44, 45, 46, 47, 48, 49, 50, 51