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September 1, 2014

September 1, 2014

Posted by **Cassidy** on Monday, August 26, 2013 at 11:38am.

I'm having a hard time to solve this problem >.<

- 8th Grade Math -
**Anon**, Monday, August 26, 2013 at 12:27pmcancel out the denominator by multiplying by greatest common factor so 2.

2(5/2t-t)=2(3+3/2t)

so now equation is 5t-2t=6+3t

then solve. 3t=6+3t

you should get no solution

- 8th Grade Math -
**Cassidy**, Monday, August 26, 2013 at 1:10pmI don't understand....

- 8th Grade Math -
**PsyDAG**, Monday, August 26, 2013 at 1:12pmAnon failed to notice that t is also in the denominator.

Multiply both sides by 2t.

5 - 2t^2 = 6t + 3

Combine like terms.

2 - 2t^2 -6t = 0

Multiply by -1.

2t^2 + 6t - 2 = 0

I also get no solution, but at least my equation is correct.

- 8th Grade Math -
**Ms. Sue**, Monday, August 26, 2013 at 1:13pmAnon is correct.

3t=6+3t

When we subtract 3t from both sides of the equation, we no longer have an equation. 0 = t is meaningless; therefore this problem has no solution.

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