Sunday

September 21, 2014

September 21, 2014

Posted by **R6** on Monday, August 26, 2013 at 9:53am.

21. -3)3 0 0 82 0 0 27

-9 27 -81 -3 9 -27

3 -9 27 1 -3 9 0

Remainder = 0 so that means x+3 is a factor of 3x6+82x3+27

- Algebra -
**bobpursley**, Monday, August 26, 2013 at 10:12amthe zeroes in 3 0 0 82 0 0 27

those are coefficents of the polynomial

the polynomial is 3x^6+0x^5+0x^4+82x^3+0x^2 + 0x + 27

or, 3 0 0 82 0 0 27

yes, your conclusion is correct. You can prove it by long division.

- Algebra -
**Reiny**, Monday, August 26, 2013 at 10:17amFrom your post I concluded that you had

3x^6 - 82x^3 + 27 ÷ (x+3)

the expression did not contain any x^5 , x^4 , x^2 and x terms so in your synthetic division setup you have to replace these with 0's

that is why your top row looks like

-3**|**3 0 0 82 0 0 27

I assume you know the procedure for synthetic division, the second row is correct

the last row is your "answer row" and since we started with x^6 .... divided by x+3, the answer must start with x^5

so

3x^6 - 82x^3 + 27 ÷ (x+3)

= 3x^5 - 9x^4 + 27x^3 + x^2 - 3x + 9 with zero remainder

and yes, x+3 is a factor since our remainder was zero, the last number in the last row.

**Answer this Question**

**Related Questions**

Pre Calc - I am familiar with this type of problem but can't seem to get the ...

Pre Calc (For Reiny) - Thanks so much your method worked perfectly! My solution ...

Algebra - Divide using long division or synthetic division. (21x^3 - 7)/(3x - 1...

Algebra - Divide using long division or synthetic division. (21x^3 - 7)/(3x - 1...

math- finding zeros - Using the given zero, find all the zeroes and write a ...

Precalc - Hello, good afternoon. I need help with my precalc hw. we are learning...

Precalculus(URGENT) - solve the problem 2xcubed-17xsquared+31x+20 given that 5 ...

Algebra - (4x^3-9x+8x^2-18)/(x+2)-use synthetic division to divide. I set it up ...

Algebra 2 help please :) - What is a cubic polynomial function in standard form ...

ALGEBRA - Can anyone explain this in 50 words why the equation turns out like it...