Posted by **R6** on Monday, August 26, 2013 at 9:53am.

The book said to replace the x with a zero. Why are two zero's used in the division of this problem. (synthetic division)

21. -3)3 0 0 82 0 0 27

-9 27 -81 -3 9 -27

3 -9 27 1 -3 9 0

Remainder = 0 so that means x+3 is a factor of 3x6+82x3+27

- Algebra -
**bobpursley**, Monday, August 26, 2013 at 10:12am
the zeroes in 3 0 0 82 0 0 27

those are coefficents of the polynomial

the polynomial is 3x^6+0x^5+0x^4+82x^3+0x^2 + 0x + 27

or, 3 0 0 82 0 0 27

yes, your conclusion is correct. You can prove it by long division.

- Algebra -
**Reiny**, Monday, August 26, 2013 at 10:17am
From your post I concluded that you had

3x^6 - 82x^3 + 27 ÷ (x+3)

the expression did not contain any x^5 , x^4 , x^2 and x terms so in your synthetic division setup you have to replace these with 0's

that is why your top row looks like

-3 **|** 3 0 0 82 0 0 27

I assume you know the procedure for synthetic division, the second row is correct

the last row is your "answer row" and since we started with x^6 .... divided by x+3, the answer must start with x^5

so

3x^6 - 82x^3 + 27 ÷ (x+3)

= 3x^5 - 9x^4 + 27x^3 + x^2 - 3x + 9 with zero remainder

and yes, x+3 is a factor since our remainder was zero, the last number in the last row.

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