Posted by **sasha** on Sunday, August 25, 2013 at 6:07pm.

K is the midpoint of JL JL=4x-2

and JK=7. find x, KL, and JL.

Very confused , can you please show steps to working out the problem

- math -
**Steve**, Sunday, August 25, 2013 at 6:23pm
JL is the whole length, so JK is half the length. So,

7+7 = 4x-2

4x = 16

x = 4

So, JL = 4*4-2 = 14

JK = KL = 7

Actually, since they told us that JK=7, we knew right away that JL was 14, since JK was half of JL. All that nonsense about x and stuff was superfluous.

- math -
**sasha**, Sunday, August 25, 2013 at 7:04pm
thank you so much steve

## Answer This Question

## Related Questions

- math - 1-sin^2x/cosx = sin^2x/2sinx Please help me figure out this one, can you ...
- Algebra 2 Urgent! please Help! - simplfy (10x^2-6x-x^3)+(9x+x^3+5x^2) please ...
- Algebra - Help please-I'm doing something wrong- Solve 8x^2 + 6x + 5 = 0 I'm ...
- chem - If 1.0 L of 0.2 M Ca(OH)2 is added to 2.5 L of 0.1 M HCl, the pH of the ...
- geometry - in triangle GHJ, k(2,3) is the midpoint of GH, l(4,1) is the midpoint...
- Pre-Cal - Evaluate the following. Show you work: A). tan^-1(tan(5π/6)) B). ...
- Algebra II - Find (f+g)(x),(f-g)(x),(f*g)(x), and (f/g)(x) for each f(x) and g(x...
- Trig - Can somebody please help me find the domain of: 1 / cos4x If there are ...
- Math - Determine the zeros of the function 3x^2 -8=10x. I know I rewrite it as ...
- Geometry - Find the coordinates of the other endpoint of a segment with the ...

More Related Questions