Posted by **Anonymous** on Friday, August 23, 2013 at 5:07pm.

Given that

f(x)= x^3 i f x≥0

x i f x<0

which of the following functions is even?

I. f(x)

II. f(|x|)

III. |f(x)|

- Calculus -
**Steve**, Friday, August 23, 2013 at 6:19pm
f(x) is not even, since

f(-x) ≠ f(x) for x≠0,1

f(3) = 27

f(-3) = -3

----------------------

f(|x|) is even since |x| is always positive

------------------------

|f(x)| is not even, again, because x ≠ x^3 for x≠0,1

|f(3)| = 27

|f(-3)| = 3

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