Calculus
posted by Anonymous on .
Given that
f(x)= x^3 i f x≥0
x i f x<0
which of the following functions is even?
I. f(x)
II. f(x)
III. f(x)

f(x) is not even, since
f(x) ≠ f(x) for x≠0,1
f(3) = 27
f(3) = 3

f(x) is even since x is always positive

f(x) is not even, again, because x ≠ x^3 for x≠0,1
f(3) = 27
f(3) = 3