Posted by Kiki on Friday, August 23, 2013 at 1:30am.
There are 900 threedigit integers. The number of threedigit integers having at least one repeated digit is also a threedigit number. If that number is represented by abc where each letter is a digit compute ab+c.

Math  drwls, Friday, August 23, 2013 at 1:59am
Already answered.
math  MathMate, Saturday, May 28, 2011 at 11:00pm
Here we have 10 digits, of which the first one cannot be zero.
If the three digits are distinct, there are 9 choices for the first digit, still 9 (including zero) for the second, and 8 for the third.
So 9*9*8=648 numbers.
There are therefore 900648=252 numbers which have at least one repeated digit.
So a=2, b=5, c=2, and ab+c=25+2=1
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