Posted by **kelly** on Thursday, August 22, 2013 at 9:38pm.

Solve the system of equations

3x-y=11

-5x+y=12

2.

Perform the indicated operation and simplify (5/(x-2)+(4(x^2-2x)

3.simpify and write with only positive exponents (7x^3y^-2)/(x^-4y^9)^-3

4.

find the solution of the inequality

2x-11 is less than or equal to -4(5x-3)

5. the length of a recangle is 5 feet less than twice the width. the area is 25 square feet. using w as the variable. write an equation that can be used to calculate the width.

(2w^2-5)

- Math -
**kelly**, Thursday, August 22, 2013 at 11:12pm
Any help would be appreciated. This is for my study guide in order to do well on my test. Someone please help.

- Math -
**Steve**, Friday, August 23, 2013 at 4:52am
#1

From the first, y=3x-11

Plug that into the second:

-5x+3x-11 = 12

-2x = 23

x = -23/2

y = -91/2

Or, you can just add the equations to eliminate the y terms:

-5x = 23

...

#2 Your parentheses are unbalanced. If you mean

5/(x-2) + 4/(x^2-2x)

5/(x-2) + 4/(x(x-2))

5x/(x(x-2)) + 4/(x(x-2))

(5x+4)/(x(x-2))

(5x+4)/(x^2-2x)

#3

(7x^3y^-2)/(x^-4y^9)^-3

(x^-4y^9)^-3 = x^12 y^-27

Since you're dividing by that, you have

(7x^3y^-2)*(x^-12 y^27)

7x^-9 y^25

7y^25/x^9

- Math -
**Steve**, Friday, August 23, 2013 at 4:56am
#4.

2x-11 <= -4(5x-3)

2x-11 <= -20x + 12

22x <= 23

x <= 23/22

#5.

length is 2w-5

area is 25, so

w(2w-5) = 25

2w^2-5w = 25

2w^2 - 5w - 25 = 0

(2w+5)(w-5) = 0

w=5 (-5/2 is not a usable width)

the rectangle is a square 5x5

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