Time=distance/velocity
=20/300
=0.067secs
s = ut 1/2gt^2
s = 0*0.067 0.5*10*0:067^2
s = 0 5*0.004489
s = 0 0.0224
s = 0.022m
To find the time it takes for an object to travel a certain distance, you can use the formula Time = Distance / Velocity. In this case, the distance is given as 20 meters and the velocity is given as 300 meters per second. Plugging in these values into the formula, we get:
Time = 20 / 300 = 0.067 seconds
To find the displacement (s) of the object, we can use the formula for displacement in uniformly accelerated motion:
s = ut + (1/2)gt^2
Where:
s = displacement
u = initial velocity (which is given as 0)
t = time (0.067 seconds)
g = acceleration due to gravity (which is usually taken as 10 m/s^2)
Plugging in these values into the equation, we get:
s = 0*(0.067) + (1/2) * 10 * (0.067)^2
s = 0 + 0.5 * 10 * 0.004489
s = 0 + 5 * 0.004489
s = 0 + 0.02244
s = 0.02244 meters (or approximately 0.022 meters)
Therefore, the displacement of the object is 0.022 meters.