Monday

December 22, 2014

December 22, 2014

Posted by **Lindsay** on Tuesday, August 20, 2013 at 4:45pm.

f(x)= (x^2-x-12)/(x^2-6x+8)

I just don't understand how to find the intervals. Thanks~

- Math -
**Reiny**, Tuesday, August 20, 2013 at 9:51pmf(x)= (x^2-x-12)/(x^2-6x+8)

= (x-4)(x+3)/( (x-2)(x-4)

= (x+3)/(x-2) , x not= 4

So the function is discontinuous at x=4 and at x = 2

with a "hole" at (4, 7/2)

and a vertical asymptote at x = 2

So continuous for

x<2 OR x > 2, x not= 4

**Answer this Question**

**Related Questions**

calculus please help! - Which of the following functions f has a removable ...

Calculus - #4 - Suppose g(x)={1/(x-2) if x<1 {2x-4 if x≥1 The best ...

Calculus - #3 - Suppose g(x)={1/(x-2) if x<1 {2x-3 if x≥1 The best ...

Calculus - Suppose g(x) = { 1 / (x - 2) if x < 1 2x - 4 if x >/= 1 The ...

Calculus - #1 - Suppose g(x)={1/x+1 if x<1 {2x-1 if x≥1 The best ...

Calculus - A function f(x) is said to have a removable discontinuity at x=a if: ...

Calculus - A function f(x) is said to have a removable discontinuity at x=a if: ...

Calculus - A function f(x) is said to have a removable discontinuity at x=a if: ...

Calculus - A function f(x) is said to have a removable discontinuity at x=a if: ...

Calculus - #2 - Suppose g(x)={x^2+2x+1/x+1 if x<1 {2x if x≥1 The best ...