1. A sample of neon is collected at 1273.51 kPa and 12.0 oC. It has a volume of 2.25 L. What would be the volume of this gas at STP?

(2.25 L) x (1273.51 kPa / 101.3 kPa) x (0 + 273.15 K) / (12.0 + 273.15 K) = 27.1 L

2.A sample of argon has a volume of 1205 cm3 when its temperature is -44.0 oC and its pressure is .937 kPa. What would be the volume of the argon at STP?

(1205 cm^3) x (0.00 + 273.15 K) / (-44.0 + 273.15 K) x (0.937 kPa / 101.3 kPa) =
13.3 cm^3

3. A student collects a 13.00 x 102 cm3 sample of hydrogen at 22.0 oC and 91.9 kPa. What volume would the hydrogen occupy at STP?
3.
(1300 cm^3) x (0.00 + 273.15 K) / (22.0 + 273.15 K) x (91.9 kPa / 101.3 kPa) =
1091 cm^3

2 is wrong. Perhaps you missed a decimal place.

To calculate the volume of a gas at STP (Standard Temperature and Pressure), you can use the combined gas law equation, which incorporates the variables of pressure, volume, and temperature.

The combined gas law equation is as follows:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

Where:
P1 and P2 are the initial and final pressures,
V1 and V2 are the initial and final volumes,
T1 and T2 are the initial and final temperatures.

To solve for the final volume (V2) at STP, you need to know the initial volume (V1) and the initial temperature (T1) and pressure (P1).

In all of the examples provided, we are given the initial volume, temperature, and pressure. To calculate the volume at STP, we also need to know the STP conditions, which are typically defined as:
- Temperature (T2) = 0 °C or 273.15 K
- Pressure (P2) = 101.3 kPa or 1 atm

By substituting the known values into the combined gas law equation and solving for V2, you can determine the volume at STP.

Let's go through the calculations for each example:

1. Neon sample:
Initial pressure (P1) = 1273.51 kPa
Initial temperature (T1) = 12.0 °C or 12.0 + 273.15 K
Initial volume (V1) = 2.25 L
STP temperature (T2) = 0 °C or 273.15 K
STP pressure (P2) = 101.3 kPa

Calculating:
(V2) = (V1 * P1 * T2) / (P2 * T1)
= (2.25 L * 1273.51 kPa * 273.15 K) / (101.3 kPa * (12.0 + 273.15 K))
≈ 27.1 L

Therefore, the volume of the neon gas at STP would be approximately 27.1 L.

2. Argon sample:
Initial pressure (P1) = 0.937 kPa
Initial temperature (T1) = -44.0 °C or -44.0 + 273.15 K
Initial volume (V1) = 1205 cm^3
STP temperature (T2) = 0 °C or 273.15 K
STP pressure (P2) = 101.3 kPa

Calculating:
(V2) = (V1 * P1 * T2) / (P2 * T1)
= (1205 cm^3 * 0.937 kPa * 273.15 K) / (101.3 kPa * (-44.0 + 273.15 K))
≈ 13.3 cm^3

Therefore, the volume of the argon gas at STP would be approximately 13.3 cm^3.

3. Hydrogen sample:
Initial pressure (P1) = 91.9 kPa
Initial temperature (T1) = 22.0 °C or 22.0 + 273.15 K
Initial volume (V1) = 13.00 x 10^2 cm^3
STP temperature (T2) = 0 °C or 273.15 K
STP pressure (P2) = 101.3 kPa

Calculating:
(V2) = (V1 * P1 * T2) / (P2 * T1)
= (1300 cm^3 * 91.9 kPa * 273.15 K) / (101.3 kPa * (22.0 + 273.15 K))
≈ 1091 cm^3

Therefore, the volume of the hydrogen gas at STP would be approximately 1091 cm^3.