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May 22, 2015

Homework Help: Chemistry

Posted by justin on Tuesday, August 20, 2013 at 12:48pm.

hi this seems simple but i cant figure it out.

If a 0.46 kg hot copper pan lost 9.8x103
J of heat as it cooled down to 54C, what was its
original temperature?

I used the 24.44 j/molK for heat capacity, is not this one? found on wikipedia: copper

this is how i derive my equation...
-9.8x10^3=7.24mol(24.44j/molK)(327-x)

the answer is 77C but im getting 109.39C :( please help thanks

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