Posted by justin on Tuesday, August 20, 2013 at 12:48pm.
hi this seems simple but i cant figure it out.
If a 0.46 kg hot copper pan lost 9.8x103
J of heat as it cooled down to 54°C, what was its
original temperature?
I used the 24.44 j/molK for heat capacity, is not this one? found on wikipedia: copper
this is how i derive my equation...
9.8x10^3=7.24mol(24.44j/molK)(327x)
the answer is 77C but im getting 109.39C :( please help thanks

Chemistry  DrBob222, Tuesday, August 20, 2013 at 3:43pm
I used 0.385 J/g*C and came up with the same answer. You can prove that 109.39 is correct (although that's too many significant figures to use) this way.
10954 = 55.39
55.39 x 0.385 J/g x 460 g = 980.9 J.
55.39 x 24.44 x (460/63.54) = 980.03 J.

Chemistry  justin, Tuesday, August 20, 2013 at 4:32pm
thanks!!!! it was an exercise from study guide it just gave the answer not the solution. might be correction
Answer This Question
Related Questions
 chemistry  A pan full of hot salt water, NaCl(aq), is cooled and NaCl(s) ...
 Energy Transfer in Natural Systems  If u reach into a hot oven to remove a ...
 Chemistry!  The heat lost or gained by a system is related to its temperature ...
 Chemistry  The heat lost or gained by a system is related to its temperature ...
 Chemistry  Can someone please help me with the following? How do I find the ...
 Chemistry  I have this problem: How much heat energy is required to raise the ...
 General Chemistry  If 50.0grams of copper initially at 145.0 C is put into 150....
 Chemistry  The specific heat of solid copper is 0.385 J/g*C. What thermal ...
 Chemistry  The specific heat of solid copper is 0.385 J/g*C. What thermal ...
 physics  If the specific heat of water = 4190 J/kg /°C and a total of 120g of ...
More Related Questions