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April 19, 2014

Homework Help: Chemistry;HELP

Posted by Unknown on Tuesday, August 20, 2013 at 12:27pm.

How did he get 15 moles?

What is the molarity of a 5.00 x 102 ml solution containing 2490 g of KI?


5.00*10^2ml = 500ml = .5L

KI has molar mass 166, so you have 15 moles of KI

15moles/.5L = 30moles/L = 30M

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