Posted by Unknown on Tuesday, August 20, 2013 at 12:20pm.
Help? I'm stuck.
For each graph, find (a)AB to the nearest tenth and (b)the coordinates of the midpoint of AB.
1. Coordinates are A(9, 6) B(6,6)
2.A(2,2) B(8,6)
3. A(0,3) B(2,2)

Geometry, Help  Steve, Tuesday, August 20, 2013 at 12:31pm
just use the distance formula: d = √(∆x^2 + ∆y^2)
for #2, that would be
d = √((8(2))^2 + (6(2))^2)
= √(10^2 + (4)^2)
= √116
= 2√29

Geometry, Help  Unknown, Tuesday, August 20, 2013 at 12:38pm
would you divide 2 by 29?

Geometry, Help  Unknown, Tuesday, August 20, 2013 at 12:42pm
Is #1 184.2?

Geometry, Help  Steve, Tuesday, August 20, 2013 at 12:46pm
#1 is √(225+144) = √369 = 19.2

Geometry, Help  Steve, Tuesday, August 20, 2013 at 12:47pm
for #2 the midpoint is (3,4)
That is the average of the endpoints

Geometry, Help  Unknown, Tuesday, August 20, 2013 at 12:52pm
I got 369 and divided by 2. How's you get that answer?

Geometry, Help  Unknown, Tuesday, August 20, 2013 at 12:55pm
SORRY! I was squaring it. Thanks for your help.

Geometry, Help  Unknown, Tuesday, August 20, 2013 at 1:20pm
is one's midpoint answer (1.5,6)?

Geometry, Help  Steve, Tuesday, August 20, 2013 at 2:36pm
No, it's (1.5,0) !!
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