Help? I'm stuck.

For each graph, find (a)AB to the nearest tenth and (b)the coordinates of the midpoint of AB.

1. Coordinates are A(-9, -6) B(6,6)

2.A(-2,-2) B(8,-6)

3. A(0,3) B(-2,-2)

just use the distance formula: d = √(∆x^2 + ∆y^2)

for #2, that would be
d = √((8-(-2))^2 + (-6-(-2))^2)
= √(10^2 + (-4)^2)
= √116
= 2√29

would you divide 2 by 29?

Is #1 184.2?

#1 is √(225+144) = √369 = 19.2

for #2 the midpoint is (3,-4)

That is the average of the endpoints

I got 369 and divided by 2. How's you get that answer?

SORRY! I was squaring it. Thanks for your help.

is one's midpoint answer (-1.5,-6)?

No, it's (-1.5,0) !!

Woah yall mad or sumthin?