Geometry, Help
posted by Unknown on .
Help? I'm stuck.
For each graph, find (a)AB to the nearest tenth and (b)the coordinates of the midpoint of AB.
1. Coordinates are A(9, 6) B(6,6)
2.A(2,2) B(8,6)
3. A(0,3) B(2,2)

just use the distance formula: d = √(∆x^2 + ∆y^2)
for #2, that would be
d = √((8(2))^2 + (6(2))^2)
= √(10^2 + (4)^2)
= √116
= 2√29 
would you divide 2 by 29?

Is #1 184.2?

#1 is √(225+144) = √369 = 19.2

for #2 the midpoint is (3,4)
That is the average of the endpoints 
I got 369 and divided by 2. How's you get that answer?

SORRY! I was squaring it. Thanks for your help.

is one's midpoint answer (1.5,6)?

No, it's (1.5,0) !!