Posted by Unknown on .
Help? I'm stuck.
For each graph, find (a)AB to the nearest tenth and (b)the coordinates of the midpoint of AB.
1. Coordinates are A(9, 6) B(6,6)
2.A(2,2) B(8,6)
3. A(0,3) B(2,2)

Geometry, Help 
Steve,
just use the distance formula: d = √(∆x^2 + ∆y^2)
for #2, that would be
d = √((8(2))^2 + (6(2))^2)
= √(10^2 + (4)^2)
= √116
= 2√29 
Geometry, Help 
Unknown,
would you divide 2 by 29?

Geometry, Help 
Unknown,
Is #1 184.2?

Geometry, Help 
Steve,
#1 is √(225+144) = √369 = 19.2

Geometry, Help 
Steve,
for #2 the midpoint is (3,4)
That is the average of the endpoints 
Geometry, Help 
Unknown,
I got 369 and divided by 2. How's you get that answer?

Geometry, Help 
Unknown,
SORRY! I was squaring it. Thanks for your help.

Geometry, Help 
Unknown,
is one's midpoint answer (1.5,6)?

Geometry, Help 
Steve,
No, it's (1.5,0) !!