Posted by **Unknown** on Tuesday, August 20, 2013 at 12:20pm.

Help? I'm stuck.

For each graph, find (a)AB to the nearest tenth and (b)the coordinates of the midpoint of AB.

1. Coordinates are A(-9, -6) B(6,6)

2.A(-2,-2) B(8,-6)

3. A(0,3) B(-2,-2)

- Geometry, Help -
**Steve**, Tuesday, August 20, 2013 at 12:31pm
just use the distance formula: d = √(∆x^2 + ∆y^2)

for #2, that would be

d = √((8-(-2))^2 + (-6-(-2))^2)

= √(10^2 + (-4)^2)

= √116

= 2√29

- Geometry, Help -
**Unknown**, Tuesday, August 20, 2013 at 12:38pm
would you divide 2 by 29?

- Geometry, Help -
**Unknown**, Tuesday, August 20, 2013 at 12:42pm
Is #1 184.2?

- Geometry, Help -
**Steve**, Tuesday, August 20, 2013 at 12:46pm
#1 is √(225+144) = √369 = 19.2

- Geometry, Help -
**Steve**, Tuesday, August 20, 2013 at 12:47pm
for #2 the midpoint is (3,-4)

That is the average of the endpoints

- Geometry, Help -
**Unknown**, Tuesday, August 20, 2013 at 12:52pm
I got 369 and divided by 2. How's you get that answer?

- Geometry, Help -
**Unknown**, Tuesday, August 20, 2013 at 12:55pm
SORRY! I was squaring it. Thanks for your help.

- Geometry, Help -
**Unknown**, Tuesday, August 20, 2013 at 1:20pm
is one's midpoint answer (-1.5,-6)?

- Geometry, Help -
**Steve**, Tuesday, August 20, 2013 at 2:36pm
No, it's (-1.5,0) !!

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