posted by sohan sah on .
show that the altitudes of equivilent root3/2 of a side
Wouldn't be easier just to post the problem as stated? The language above is gibberish. How about
show that the altitudes of an equilateral triangle are √3/2 of a side
Draw the altitude.
Now you have a right triangle, with legs h, s/2 and hypotenuse s.
Using the Pythagorean Theorem,
h^2 + (s/2)^2 = s^2
h^2 + s^2/4 = s^2
h^2 = 3/4 s^2
h = √3/2 s