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An oceanic depth-sounding vessel surveys the ocean bottom with ultrasonic waves that travel at 1530 m/s in seawater. Show that when the time delay of an echo to the ocean floor below is 4 s, the depth of the water is 3060 m.

d=vt=1530ms x 2 =3060

not sure if i did it correct or missed a step..i should work on not seconding guessing myself

  • Physics -

    your equation is correct. What does it represent? How does the "2" in your equation relate to the "4" in the problem?

  • Physics -

    distance traveled = time x speed
    the 2 is half of 4s

  • Physics -

    thank you, i was making sure i was correct before i responded back to steve.

    i thought the 2 represented half of 4s, which is the delay of the echo

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