Physics
posted by Tiffany on .
An oceanic depthsounding vessel surveys the ocean bottom with ultrasonic waves that travel at 1530 m/s in seawater. Show that when the time delay of an echo to the ocean floor below is 4 s, the depth of the water is 3060 m.
d=vt=1530ms x 2 =3060
not sure if i did it correct or missed a step..i should work on not seconding guessing myself

your equation is correct. What does it represent? How does the "2" in your equation relate to the "4" in the problem?

distance traveled = time x speed
the 2 is half of 4s 
thank you, i was making sure i was correct before i responded back to steve.
i thought the 2 represented half of 4s, which is the delay of the echo