How many moles are in 27.5 grams of LiCl? Show all work!
I'm surprised you can't use that information Steve gave you for the preparation of the LiCl solution earlier.
mol = grams/molar mass
I could I just forgot the equation. Sorry...
To find the number of moles in 27.5 grams of LiCl, you need to use the molar mass of LiCl and the formula:
Number of moles = Mass (in grams) / Molar mass (in grams/mol)
1. First, let's calculate the molar mass of LiCl:
- The atomic mass of Li (Lithium) is approximately 6.94 g/mol.
- The atomic mass of Cl (Chlorine) is approximately 35.45 g/mol.
- LiCl is composed of 1 Li atom and 1 Cl atom, so its molar mass is:
Molar mass of LiCl = (Atomic mass of Li) + (Atomic mass of Cl)
= 6.94 g/mol + 35.45 g/mol
= 42.39 g/mol
2. Now that we have the molar mass of LiCl, we can plug it into the formula:
Number of moles = Mass (in grams) / Molar mass (in grams/mol)
Number of moles = 27.5 g / 42.39 g/mol
3. Calculate the number of moles:
Number of moles = 0.649 mol (rounded to three decimal places)
Therefore, there are approximately 0.649 moles of LiCl in 27.5 grams.