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If the sum of the squares of the roots of the quadratic equation ax^2 + bx + c = 0 is m:n, prove that b^2= 2ac + 4a^2

I really have no idea how to prove it so pls help

  • maths -

    one root: [-b+sqrt(b^2-4ac)]/2a
    squared: b^2 -2bsqrt(b^2-4ac) + b^2-4ac]/4a^2

    second root : [-b-sqrt(b^2-4ac)]/2a
    squared: b^2 +2bsqrt(b^2-4ac) + b^2-4ac]/4a^2

    sum: [ 4 b^2 - 8ac ] / 4a^2

    = [b^2 -2ac]/a^2
    now I have no idea what m:n means so you have to take it from there.

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