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March 31, 2015

March 31, 2015

Posted by **disha** on Saturday, August 17, 2013 at 6:02pm.

- algebra -
**Damon**, Saturday, August 17, 2013 at 6:56pm-B = -2a+b+c

B^2 = 4a^2-4ab-4ac+b^2+2bc+c^2

-4AC = -4a^2+4ab+4ac+8b^2-20bc+8c^2

so

B^2-4AC=9b^2-18bc+9c^2 = 9(b^2-2bc+c^2)

=9(b-c)^2 whew!

sqrt(B^2-4AC) = 3(b-c) = 3b - 3c

so

-B+/-sqrt(B^2-4AC) = -2a+b+c +/- (3b-3c)

= -2a+4b-2c or -2a-2b+4c

divide those by 2A

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