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October 20, 2014

October 20, 2014

Posted by **disha** on Saturday, August 17, 2013 at 5:36pm.

- algebra -
**Steve**, Saturday, August 17, 2013 at 5:46pmwell

p = (5±√13)/2

q = (5±√13)/2

If p≠q then one is (5+√13)/2 and the other is (5-√13)/2

(5+√13)/(5-√13) = (19+5√13)/6

(5-√13)/(5+√13) = (19-5√13)/6

So, the equation is

(x-((19+5√13)/6))(x-((19-5√13)/6)) = 0

(6x-19-5√13)(6x-19+5√13) = 0

(6x-19)^2 - 325 = 0

36x^2 - 228x + 36 = 0

3x^2 - 19x + 3 = 0

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