Posted by Jayden Haddy on .
If the ratio of the roots of the quadratic equation ax^2 + bx +c =0 is m:n
prove that mnb^2=(m+n)^2 ac

maths 
Sasuke,
sum: m + n = b/a
product: mn = c/a
substitute. when proving, you only manipulate/solve one side.
mnb^2=(m+n)^2 ac
(c/a)(b^2) =? (ac)(m+n)^2
(c/a)[a(m + n)]^2 =? (ac)(m+n)^2
(c/a)(a^2)(m+n)^2 =? (ac)(m+n)^2
(ac)(m+n)^2 = (ac)(m+n)^2
this problem is pretty much the same as the one you posted earlier. you should also check Naruto's answer on that post. 
maths 
Writeacher,
Gee! Naruto and Sasuke seem to be the same person!!