Posted by **Jayden Haddy** on Saturday, August 17, 2013 at 6:01am.

If the ratio of the roots of the quadratic equation ax^2 + bx +c =0 is m:n

prove that mnb^2=(m+n)^2 ac

- maths -
**Sasuke**, Saturday, August 17, 2013 at 6:34am
sum: m + n = -b/a

product: mn = c/a

substitute. when proving, you only manipulate/solve one side.

mnb^2=(m+n)^2 ac

(c/a)(b^2) =? (ac)(m+n)^2

(c/a)[a(m + n)]^2 =? (ac)(m+n)^2

(c/a)(a^2)(m+n)^2 =? (ac)(m+n)^2

(ac)(m+n)^2 = (ac)(m+n)^2

this problem is pretty much the same as the one you posted earlier. you should also check Naruto's answer on that post.

- maths -
**Writeacher**, Saturday, August 17, 2013 at 10:25am
Gee! Naruto and Sasuke seem to be the same person!!

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