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December 22, 2014

December 22, 2014

Posted by **Jayden Haddy** on Saturday, August 17, 2013 at 5:59am.

- maths -
**Naruto**, Saturday, August 17, 2013 at 6:28amsum = p

product = q

let a & b the roots

a + b = p

ab = q

since a & b are consecutive integers (i.e. b = a+1):

2a + 1 = p

a^2 + a = q

substitute.

p^2 - 4q -1 = 0

4a^2 + 4a + 1 - 4a^2 + 4a - 1 = 0

indeed,

0 = 0

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