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October 21, 2014

October 21, 2014

Posted by **Roosevelt** on Wednesday, August 14, 2013 at 1:29pm.

1. y= -2x -4; (1, 3) how do I write the equation of a line parallel to the given line but passing through the given point

2. y= 3x + 3; (1,1) how do I write the equation of a line perpendicular to the given line but passing through the given point

- Algebra -
**Steve**, Wednesday, August 14, 2013 at 3:49pmIt must have the same slope: -2

Now you have a point and a slope, so the line is

y-3 = -2(x-1)

same idea, but you want the perpendicular slope, which is the negative reciprocal of the line's slope: -1/3

y-1 = -1/3(x-1)

review the various forms of the equation of a line:

standard

point-slope

two-point

slope-intercept

- Pre- Algebra -
**Henry**, Wednesday, August 14, 2013 at 6:54pm1. Y = -2x - 4. (1,3).

Parallel lines have equal slopes:

m1 = m2 = -2.

Y = mx + b = 3

-2*1 + b = 3

b = 3+2 = 5

Eq: Y = -2x + 5

2. Y = 3x+3. (1,1).

The slope of the line is equal to the negat1ive reciprocal of the slope of the given line.

m1 = 3

m2 = -1/3.

Y = mx + b = 1

(-1/3)*1 + b = 1

b = 1 + 1/3 = 1 1/3 = 4/3

Eq: Y = (-1/3)x + 4/3

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