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May 25, 2015

Homework Help: chemistry

Posted by raghu on Tuesday, August 13, 2013 at 5:22am.

50.0 mL of a 0.00200 M Cd^2+ solution is titrated with 0.00400 M EDTA in the
presence of 0.0750 M NH3 buffered at pH = 9.00. Determine pCd^2+ when 28.5 mL of EDTA solution have been added.
Cd^2+ + Y^4- ? CdY^2- Kf= 3.16 x 10^16
Cd^2+ + NH3 ? CdNH3^2+ 1 = 3.24 x 10^2
Cd^2+ + 2 NH3 ? Cd(NH3)2^2+ 2 = 2.95 x 10^4
Cd^2+ + 3 NH3 ? Cd(NH3)3^2+ 3 = 5.89 x 10^5
Cd^2+ + 4 NH3 ? Cd(NH3)4^2+ 4 = 3.63 x 10^6
(alpha)aCd^2+ = 1.80 x 10^-3
(alpha)aY^4- = 0.041
Chemistry

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