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March 31, 2015

March 31, 2015

Posted by **Arch** on Monday, August 12, 2013 at 8:19am.

- Mathematics -
**Steve**, Monday, August 12, 2013 at 1:27pmIf the length of the corners cut off is s, the diagonal length is s√2.

The area of each triangle is thus 1/2 (2s^2) = s^2

Now, we know that 2s + s√2 = n, so

s = n/(1+√2)

The area cut off is thus 4n^2/(3+2√2) = 4(3-√8)n^2

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