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April 18, 2014

April 18, 2014

Posted by **Anonymous** on Monday, August 12, 2013 at 2:12am.

- math -
**Jai**, Monday, August 12, 2013 at 2:57amRepresent the unknown with variables:

Let x = amount of premium grade gasoline sold in gallons

Let x+420 = amount of regular grade gasoline sold in gallons (according to the third statement)

Then we set up the equation. We know that the total worth of gasoline sold is 10,957. Therefore, we multiply the costs per each gallon of regular & premium grade by their respective amounts and get the total:

2.55x + (2.30)(x+420) = 10957

Solving for x,

2.55 + 2.3x + 966 = 10957

4.85x = 10957 - 966

4.85x = 9991

x = 2060 gallons of premium grade, and

x+420 = 2480 gallons of regular grade

Hope this helps~ :)

- math -
**Kayla**, Monday, August 19, 2013 at 5:10pmgbjgv

- math -
**Kayla**, Monday, August 19, 2013 at 5:10pmgbjgv

- teasley middle school -
**brandon**, Wednesday, August 21, 2013 at 6:37pmEquations

- teasley middle school -
**brandon**, Wednesday, August 21, 2013 at 6:38pmEquations

- teasley middle school -
**brandon**, Wednesday, August 21, 2013 at 6:46pmEquations

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