how did they find the answer of 15 atoms if the question is 5(nh4)2 so4
To find the answer of how many atoms are present in the compound 5(NH4)2SO4, you need to break down the compound into its constituent elements and calculate the total number of atoms.
1. Start by identifying the elements in the compound:
- 5 represents the coefficient in front of the entire compound.
- NH4 represents the ammonium ion, which consists of one nitrogen atom (N) and four hydrogen atoms (H).
- SO4 represents the sulfate ion, which consists of one sulfur atom (S) and four oxygen atoms (O).
2. Determine the number of atoms for each element:
- The coefficient of 5 indicates that you need to multiply the number of atoms in NH4 and SO4 by 5.
- In NH4, there is one nitrogen atom and four hydrogen atoms. Multiply both by 5.
- In SO4, there is one sulfur atom and four oxygen atoms. Multiply both by 5.
3. Calculate the total number of atoms:
- Multiply the number of atoms for each element by the coefficient of 5.
- For nitrogen (N), multiply 1 atom by 5 = 5 atoms.
- For hydrogen (H), multiply 4 atoms by 5 = 20 atoms.
- For sulfur (S), multiply 1 atom by 5 = 5 atoms.
- For oxygen (O), multiply 4 atoms by 5 = 20 atoms.
4. Sum up the total number of atoms:
- Add up the number of atoms for each element.
- 5 nitrogen atoms (N) + 20 hydrogen atoms (H) + 5 sulfur atoms (S) + 20 oxygen atoms (O) = 50 atoms in total.
Therefore, the answer is that there are 50 atoms in 5(NH4)2SO4.