Posted by **Anonymous** on Sunday, August 11, 2013 at 7:54am.

If m and n are integers such that mn is even, then m is even or n is even.

how can i prove this using contraposition?

- DISCRETE MATHS -
**Steve**, Sunday, August 11, 2013 at 6:07pm
if both are odd, we can let

m = 2a+1

n = 2b+1

mn = (2a+1)(2b+1) = 4ab+2a+2b**+1**

so, mn is odd if m and n are both odd.

So, if mn is even, then m and n cannot both be odd.

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