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April 1, 2015

April 1, 2015

Posted by **Dillon** on Saturday, August 10, 2013 at 6:38pm.

Show that the water pressure at the bottom of the 50-m-high water tower in Figure 5.3 is 490,000 N/m2, or is approximately 500 kPa.

- Physics -
**Damon**, Saturday, August 10, 2013 at 6:51pmOne way:

How much does a column of water one meter square at the bottom and 50 m high weigh?

Density of water = 1000 Kg /m^3

Volume of column = 50*1 = 50 m^3

so

mass of the column = 50,000 Kg

weight = m g = 9.81 * 50,000 = 490,500 Newtons spread over one m^2 so

490,000 N/m^2

another way

pressure = rho g h

= 1000 * 9.81 * 50 = 490,500 N/m^2 again

since a Pascal is a Newton/meter^2 we have already answered the second part, about 500 * 10^3 Pascals

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