Posted by Angela on .
using the formula W=33-(10.45 + 10sqrtv-v (33- T)/22 how do I find the wind chill temperatue for the following given: T=)c, V=15m/sec, T= -10C, V=20m/sec?
I'd say, just plug in the numbers:
W = 33-(10.45 + 10√v - v (33- T)/22
= 33 - (10.45 + 10√20 - 20(33-(-10))/22
The only problem I see is that your parentheses are unbalanced. Fix that and just evaluate the expression.