Posted by Anonymous on .
Solve the simultaneous equations in Z24,
3x+4y=18
12x+7y=4
Thanks!

Math 
Reiny,
1st times 4 > 12x + 16y = 72
2nd as is > 12x + 7y = 4
subtract them:
9y = 68
y = 68/9
back in 1st:
3x + 4(68/9) = 18
3x = 18  272/9 = 110/9
x = 110/27