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October 30, 2014

October 30, 2014

Posted by **beverly** on Wednesday, August 7, 2013 at 9:57am.

elimination method

- algebra -
**Reiny**, Wednesday, August 7, 2013 at 10:27amlet's eliminate the y's

1st times 7 --> 49x -63y = 91

2nd times 9 -> 81x + 63y = 819

add them:

130x = 910

x = 7

back into 2nd ...

9(7) + 7y = 91

7y = 28

y = 4

x=7 , y = 4

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