Given that csc θ = -4 and tan θ > 0, find the exact value of
b. sin θ
c. cos θ
e. sec θ
f. cot θ
Trig - Reiny, Wednesday, August 7, 2013 at 8:12am
same as the others ....
cscØ = -4
so sinØ = -1/4
we also know that tanØ>0 so
the sine is negative and the tangent is positive ---> Ø must be in III
since sinØ = -1/4, in III, y = -1, r = 4
by Pythagoras and the CAST rule
x = -√15
The rest is now easy, just use your definitions.
let me know what you get.
cotØ = x/y = -√15/-1 = √15