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April 18, 2015

April 18, 2015

Posted by **Paula** on Wednesday, August 7, 2013 at 5:20am.

a. x

b. sin θ

c. cos θ

d. r

e. sec θ

f. cot θ

- Trig -
**Reiny**, Wednesday, August 7, 2013 at 8:12amsame as the others ....

cscØ = -4

so sinØ = -1/4

we also know that tanØ>0 so

the sine is negative and the tangent is positive ---> Ø must be in III

since sinØ = -1/4, in III, y = -1, r = 4

by Pythagoras and the CAST rule

x = -√15

The rest is now easy, just use your definitions.

let me know what you get.

e.g.

cotØ = x/y = -√15/-1 = √15

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