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November 22, 2014

November 22, 2014

Posted by **Paula** on Wednesday, August 7, 2013 at 5:19am.

a. y

b. sin θ

c. sec θ

d. tan θ

- Trig -
**Reiny**, Wednesday, August 7, 2013 at 8:06amIf cosØ = 5/13 and Ø is in IV , then using the standard definition of cos Ø = x/r

we have x=5, r=13, then

5^2 + y^2 = 13^2

y^2 = 144

and in IV ....

a) y = -12

b) sinØ = -12/13

c) secØ = 13/5

d) tanØ = y/x = -12/5

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