Posted by **3.1415926...** on Tuesday, August 6, 2013 at 3:28pm.

Four circles of unit radius are drawn with centers (1,0), (-1,0), (0,1), and (0,-1). A circle with radius 2 is drawn with the origin as its center. What is the area of all points which are contained in an odd number of these 5 circles? (Express your answer in the form "a pi + b" or "a pi - b", where a and b are integers.)

Can you tell what the answer is? I want a clear explanation too. Thanks!!!!!!

- MATH -
**Steve**, Tuesday, August 6, 2013 at 3:44pm
the small circles intersect in lens-shaped areas of pi/2 - 1

each small circle has area pi

The large circle has area 4pi

The points in the lenses and the large circle outside the small circles lie in 1 or 3 circles.

4pi - 4(pi) + 4(pi/2-1) = 2pi-4

- MATH -
**mathemagiacian**, Wednesday, August 7, 2013 at 12:33pm
That is not right.

- MATH -
**Steve**, Thursday, August 8, 2013 at 12:30am
So, if it's not right, maybe you could let us know where we went wrong. The idea is to help here, you know.

- MATH -
**Anonymous**, Sunday, November 24, 2013 at 1:21pm
the answer is 4pi-8 . FOR SURE!!

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