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March 25, 2017

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A shot-putter releases the 16lbs shot at an angle of 41 degrees/ Of the shot travels a horizontal distance of 34m to reach its peak at midflight, how high did the shot go and what is the displacement of the resulting vector at midflight?

  • Math - ,

    y = x tanθ - g/(2 (v cosθ)^2) x^2
    = .86x - 8.6/v^2 x^2

    y reaches its max when x = 5/v^2

    v^2/20 = 34
    v = 26

    y = .86x - .0126x^2
    y(34) = .86(34) - .0126 (34^2) = 14.67

    Now just figure the displacement and you're done.

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