A Rolaids tablet contains calcium carbonate to neutralize stomach acid. One Rolaids tablet requires 44.55 mL of 0.448 M hydrochloric acid to convert its calcium carbonate into calcium chloride, carbon dioxide and water. How many grams of calcium carbonate are there in one Rolaids tablet?

CaCO3 + 2HCl ==> CaCl2 + H2O + CO2

mols HCl = M x L = ?
mols CaCO3 = 1/2 that (see the coefficients in the balanced equation).
grams CaCO3 = mols x molar mass = ?

To find the number of grams of calcium carbonate in one Rolaids tablet, we need to use the equation for the reaction between calcium carbonate and hydrochloric acid:

CaCO3 + 2HCl -> CaCl2 + CO2 + H2O

From the equation, we can see that one mole of calcium carbonate reacts with 2 moles of hydrochloric acid.

First, let's calculate the number of moles of hydrochloric acid used in the reaction.
We are given:
Volume of hydrochloric acid = 44.55 mL = 0.04455 L (1 mL = 0.001 L)
Molarity of hydrochloric acid = 0.448 M

Using the formula:
moles = volume x concentration
moles of HCl = 0.04455 L x 0.448 M
moles of HCl = 0.01994 moles

Since the stoichiometric coefficient of calcium carbonate is 1, the number of moles of calcium carbonate used in the reaction is also 0.01994 moles.

Now, we need to determine the molar mass of calcium carbonate.
The molar mass of calcium (Ca) is 40.08 g/mol, and the molar mass of carbon (C) is 12.01 g/mol, and the molar mass of oxygen (O) is 16.00 g/mol.

The molar mass of calcium carbonate (CaCO3) can be calculated as follows:
molar mass = (molar mass of calcium) + (molar mass of carbon) + 3 x (molar mass of oxygen)
molar mass of CaCO3 = 40.08 g/mol + 12.01 g/mol + 3 x 16.00 g/mol
molar mass of CaCO3 = 100.09 g/mol

Finally, we can calculate the mass of calcium carbonate in one Rolaids tablet:
mass = moles x molar mass
mass of calcium carbonate = 0.01994 moles x 100.09 g/mol
mass of calcium carbonate = 1.997 g

Therefore, there are approximately 1.997 grams of calcium carbonate in one Rolaids tablet.

To find the number of grams of calcium carbonate in one Rolaids tablet, we need to use the given information about the amount of hydrochloric acid required for the reaction.

First, we can determine the number of moles of hydrochloric acid required by using the molarity and volume of the acid. The given molarity is 0.448 M, and the volume used is 44.55 mL.

Moles of hydrochloric acid = (0.448 mol/L) x (0.04455 L) = 0.01995 mol

According to the balanced chemical equation, the reaction between calcium carbonate (CaCO3) and hydrochloric acid (HCl) is as follows:

CaCO3 + 2HCl -> CaCl2 + CO2 + H2O

From the balanced equation, we can see that 1 mole of calcium carbonate reacts with 2 moles of hydrochloric acid. Therefore, the moles of calcium carbonate can be calculated as follows:

Moles of calcium carbonate = 0.01995 mol / 2 = 0.009975 mol

The molar mass of calcium carbonate (CaCO3) can be calculated by summing the atomic masses of its constituents: 1 atom of calcium (Ca) with a mass of 40.08 g/mol, 1 atom of carbon (C) with a mass of 12.01 g/mol, and 3 atoms of oxygen (O) with a total mass of 3 x 16.00 g/mol = 48.00 g/mol.

Molar mass of calcium carbonate (CaCO3) = (40.08 g/mol) + (12.01 g/mol) + (48.00 g/mol) = 100.09 g/mol

Finally, we can calculate the mass of calcium carbonate in one Rolaids tablet by multiplying the moles of calcium carbonate by its molar mass:

Mass of calcium carbonate = 0.009975 mol x 100.09 g/mol = 0.997 g

Therefore, there are approximately 0.997 grams of calcium carbonate in one Rolaids tablet.