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March 3, 2015

March 3, 2015

Posted by **Anonymous** on Monday, August 5, 2013 at 11:57am.

- Calculus -
**Reiny**, Monday, August 5, 2013 at 1:43pmgiven:

y = arcsin √x

or

√x = sin y

domain: clearly 0 ≤ x ≤ 1

and the domain is : y any real number

for inverse:

interchange the x and y in

√x = sin y

to get

√y = sinx

y = sin^2 x

so f^-1 (x) = sin^2 x or (sinx)^2

verification:

http://www.wolframalpha.com/input/?i=plot+√x+%3D+sin%28y%29

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