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March 29, 2017

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Show that 480 W of power is expended by a weightlifter when lifting a 60-kg barbell a vertical distance of 1.2 m in a time interval of 1.5 s.

  • Physics - ,

    force = weight = m g = 60*9.8 = 588 Newtons

    distance = 1.2 m
    so
    potential energy gained = work done = 588*1.2 = 705.6 Joules

    power = energy/time = 705.6/1.5 = 470.4 Watts

    Perhaps your class is using g = 10 m/s instead of 9.8 m/s^2

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